Pom qm says dummy in results
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Step 3: Reduce the new matrix given in the following table by selecting the smallest value inĮach column and subtract from other values in that corresponding column. The row wise reduced matrix is shown in table below. In row A, the smallest value is 13, row B is 15, row C is 17 and row D is 12. Step 2: Reduce the matrix by selecting the smallest value in each row and subtracting from other values in that corresponding row. Step 1: The given matrix is a square matrix and it is not necessary to add a dummy row/column But the cost will remain the same for different sets of allocations.Įxample : Assign the four tasks to four operators.
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If there is no single zero allocation, it means multiple numbers of solutions exist. Strike off the remaining zeros in that column or row, and repeat the same for other assignments also. Note: While assigning, if there is no single zero exists in the row or column, choose any one zero and assign it. Step 8: Write down the assignment results and find the minimum cost/time. Repeat the process until all the assignments have been made. Strike off the remaining zeros, if any, in that row and column (X). Step 7: Take any row or column which has a single zero and assign by squaring it. Leave the elements covered by single line as it is. Subtract this smallest element with all other remaining elements that are NOT COVERED by lines and add the element at the intersection of lines. Step 6: Select the smallest element of the whole matrix, which is NOT COVERED by lines. If optimally is not reached, then go to step 6. Step 5: If Number of lines drawn = order of matrix, then optimally is reached, so proceed to step 7. Step 4: Draw minimum number of lines to cover all zeros. Step 3: Reduce the new matrix column-wise using the same method as given in step 2.
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Step 2: Reduce the matrix by selecting the smallest element in each row and subtract with other elements in that row. The assignment costs for dummy cells are always assigned as zero. Step 1: In a given problem, if the number of rows is not equal to the number of columns and vice versa, then add a dummy row or a dummy column. In the second phase, the solution is optimized on iterative basis. In the first phase, row reductions and column reductions are carried out. Assignment problem Hungarian method exampleĪn assignment problem can be easily solved by applying Hungarian method which consists of two phases.